The BigInt.asIntN()
static method truncates a BigInt
value to the given number of least significant bits and returns that value as a signed integer.
Syntax
BigInt.asIntN(bits, bigint)
Parameters
bits
- : The amount of bits available for the returned BigInt. Should be an integer between 0 and 253 - 1, inclusive.
bigint
- : The BigInt value to truncate to fit into the supplied bits.
Return value
The value of bigint
modulo 2^bits
, as a signed integer.
Exceptions
- RangeError
- : Thrown if
bits
is negative or greater than 253 - 1.
- : Thrown if
Description
The BigInt.asIntN
method truncates a BigInt
value to the given number of bits, and interprets the result as a signed integer. For example, for BigInt.asIntN(3, 25n)
, the value 25n
is truncated to 1n
:
25n = 00011001 (base 2)
^=== Use only the three remaining bits
===> 001 (base 2) = 1n
If the leading bit of the remaining number is 1
, the result is negative. For example, BigInt.asIntN(4, 25n)
yields -7n
, because 1001
is the encoding of -7
under two's complement:
25n = 00011001 (base 2)
^==== Use only the four remaining bits
===> 1001 (base 2) = -7n
Note:
BigInt
values are always encoded as two's complement in binary.
Unlike similar language APIs such as Number.prototype.toExponential, asIntN
is a static property of BigInt, so you always use it as BigInt.asIntN()
, rather than as a method of a BigInt value. Exposing asIntN()
as a "standard library function" allows interop with asm.js.
Examples
Staying in 64-bit ranges
The BigInt.asIntN()
method can be useful to stay in the range of 64-bit arithmetic.
const max = 2n ** (64n - 1n) - 1n;
BigInt.asIntN(64, max); // 9223372036854775807n
BigInt.asIntN(64, max + 1n); // -9223372036854775808n
// negative because the 64th bit of 2^63 is 1