The some() method of TypedArray instances tests whether at least one element in the typed array passes the test implemented by the provided function. It returns true if, in the typed array, it finds an element for which the provided function returns true; otherwise it returns false. It doesn't modify the typed array. This method has the same algorithm as Array.prototype.some.
Syntax
some(callbackFn)
some(callbackFn, thisArg)
Parameters
callbackFn- : A function to execute for each element in the typed array. It should return a truthy value to indicate the element passes the test, and a falsy value otherwise. The function is called with the following arguments:
element- : The current element being processed in the typed array.
index- : The index of the current element being processed in the typed array.
array- : The typed array
some()was called upon.
- : The typed array
- : A function to execute for each element in the typed array. It should return a truthy value to indicate the element passes the test, and a falsy value otherwise. The function is called with the following arguments:
thisArg- : A value to use as
thiswhen executingcallbackFn. See iterative methods.
- : A value to use as
Return value
false unless callbackFn returns a
value for a typed array element, in which case true is immediately returned.
Description
See Array.prototype.some for more details. This method is not generic and can only be called on typed array instances.
Examples
Testing size of all typed array elements
The following example tests whether any element in the typed array is bigger than 10.
function isBiggerThan10(element, index, array) {
return element > 10;
}
new Uint8Array([2, 5, 8, 1, 4]).some(isBiggerThan10); // false
new Uint8Array([12, 5, 8, 1, 4]).some(isBiggerThan10); // true