The test()
method of RegExp instances executes a search with this regular expression for a match between a regular expression and a specified string. Returns true
if there is a match; false
otherwise.
JavaScript RegExp objects are stateful when they have
the global or sticky flags
set (e.g., /foo/g
or /foo/y
). They store a
lastIndex from the previous match. Using this
internally, test()
can be used to iterate over multiple matches in a string
of text (with capture groups).
Syntax
test(str)
Parameters
str
- : The string against which to match the regular expression. All values are coerced to strings, so omitting it or passing
undefined
causestest()
to search for the string"undefined"
, which is rarely what you want.
- : The string against which to match the regular expression. All values are coerced to strings, so omitting it or passing
Return value
true
if there is a match between the regular expression and the string
str
. Otherwise, false
.
Description
Use test()
whenever you want to know whether a pattern is found in a
string. test()
returns a boolean, unlike the
String.prototype.search method (which returns the index of a match, or
-1
if not found).
To get more information (but with slower execution), use the exec() method. (This is similar to the String.prototype.match method.)
As with exec()
(or in combination with it), test()
called
multiple times on the same global regular expression instance will advance past the
previous match.
Examples
Using test()
Simple example that tests if "hello"
is contained at the very beginning of
a string, returning a boolean result.
const str = "hello world!";
const result = /^hello/.test(str);
console.log(result); // true
The following example logs a message which depends on the success of the test:
function testInput(re, str) {
const midstring = re.test(str) ? "contains" : "does not contain";
console.log(`${str} ${midstring} ${re.source}`);
}
Using test() on a regex with the "global" flag
When a regex has the global flag set,
test()
will advance the lastIndex of the regex.
(RegExp.prototype.exec also advances the lastIndex
property.)
Further calls to test(str)
will resume searching
str
starting from lastIndex
. The
lastIndex
property will continue to increase each time test()
returns true
.
Note: As long as
test()
returnstrue
,lastIndex
will not reset—even when testing a different string!
When test()
returns false
, the calling regex's
lastIndex
property will reset to 0
.
The following example demonstrates this behavior:
const regex = /foo/g; // the "global" flag is set
// regex.lastIndex is at 0
regex.test("foo"); // true
// regex.lastIndex is now at 3
regex.test("foo"); // false
// regex.lastIndex is at 0
regex.test("barfoo"); // true
// regex.lastIndex is at 6
regex.test("foobar"); // false
// regex.lastIndex is at 0
regex.test("foobarfoo"); // true
// regex.lastIndex is at 3
regex.test("foobarfoo"); // true
// regex.lastIndex is at 9
regex.test("foobarfoo"); // false
// regex.lastIndex is at 0
// (...and so on)
Specifications
Browser compatibility
See also
- Regular expressions guide
- RegExp